Question

Dato: 1 Find zeroes of quadratic polynomial -12+t+6t square​

Answer 1

Step-by-step explanation:

$6 {t}^{2} + t - 12 = 0 \\ 6 {t}^{2} - 8t + 9t - 12 = 0 \\ 2t(3t - 4) + 3(3t - 4) = 0 \\ (2t + 3)(3t - 4) = 0 \\ 2t + 3 = 0 \: \: \: \: 3t - 4 = 0 \\ 2t = - 3 \: \: \: \: \: 3t = 4 \\ t = - \frac{3}{2} \: \: \: \: \: t = \frac{4}{3}$

Hope you get your answer

Answer 2

Answer:

Step-by-step explanation:

the answer is t=-3\2