Question

dav public school class 8th
find the positive value plz​

Answer 1

$\huge\underbrace\mathcal\pink{anSwer}$

$\frac{3 {z}^{2} + 7 }{4 + {z}^{2} } = 2 \\ = > 3 {z}^{2} + 7 = 2(4 + {z}^{2} ) \\ = > 3 {z}^{2} + 7 = 8 + 2{z}^{2} \\ = > 3 {z}^{2} - 2 {z}^{2} = 8 - 7 \\ = > {z}^{2} = 1 \\ = > z = \sqrt{1} \\ = > z = 1 \: ans$

Answer 2

Question :-

$\frac{3z ^{2} + 7 }{4 + {z}^{2} } = 2$

Answer :-

3z² + 7 = 2(4+z²)

3z² + 7 = 8 + 2z²

3z² - 2z² = 8 - 7

z² = 1

z = square root 1

z = 1.