David and john started driving towards each other at 11AM and met each other at 2:30 PM on tje samw dat. david and john statted from different cities which are 420 moles apart. If davids average speed is 10 miles / hr lower than johns what is the speed of at which john has driving in miles/Hr
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Answer: John's speed = 65km/hr
David's speed = 55km/hr
Step-by-step explanation:
Let John's speed be x ml/hr.
David's speed = x-10ml/hr.
Their speeds after 3.5hrs
= 3.5x and 3.5*(x-10)
= 3.5x and 3.5x-35
ATQ, 3.5x + 3.5x-35 = 420
7x = 420+35
x = 455/7
x = 65
Speed of John = 65km/hr
Speed of David = 55km/hr.
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