David and Joseph have a total of 328 marbles. Matthew and David have 176 marbles. Joseph has 5 times as many marbles as Matthew. How many marbles does David have?
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Answered by
2
D+J=328......(i)
M+D=176.....(ii)
J=5M
ADDING i AND ii
2D+M+J= 504
2D+6M=504
D+3M=252....(iii)
SUBTRACTING (ii) AND(iii)
2M=76
M=38
38+D=176
D=176-38= 138
DAVID HAS 138 MARBLES
M+D=176.....(ii)
J=5M
ADDING i AND ii
2D+M+J= 504
2D+6M=504
D+3M=252....(iii)
SUBTRACTING (ii) AND(iii)
2M=76
M=38
38+D=176
D=176-38= 138
DAVID HAS 138 MARBLES
Answered by
2
David + Joseph = 328
Matt + David = 176 ---------------- (1)
Joseph = 5 x Matt
Total Marble = David + 5M + Matt + Davi = 504
2 David + 6 Matt = 504
2 ( Davi + 3matt ) = 504 (common Term )
Davi + 3 Matt= 504/2 =252--------------------- (2)
sub equ (1) and (2)
M + D - (D + 3m) = 252 - 176 = 76
M+ D - D -3M = 76
2M = 76
M= 76/2 =38
M=38
So From Equation (1) we can write
M + D= 176
give the value of M
38 + D = 176
D= 176-38 =138
Marble in David's hand = 138
Matt + David = 176 ---------------- (1)
Joseph = 5 x Matt
Total Marble = David + 5M + Matt + Davi = 504
2 David + 6 Matt = 504
2 ( Davi + 3matt ) = 504 (common Term )
Davi + 3 Matt= 504/2 =252--------------------- (2)
sub equ (1) and (2)
M + D - (D + 3m) = 252 - 176 = 76
M+ D - D -3M = 76
2M = 76
M= 76/2 =38
M=38
So From Equation (1) we can write
M + D= 176
give the value of M
38 + D = 176
D= 176-38 =138
Marble in David's hand = 138
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