David and Joseph have a total of 328 marbles. Matthew and David have 176 marbles. Joseph has 5 times as many marbles as Matthew. How many marbles doesDavid have?
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Let David , Joseph and Mathew have d, j and m marbles respectively.
d + j = 328 --------------(1)
d + m = 176 --------------(2)
Subtracting (2) from (1):
j - m = 328 - 176 = 152 ---(3)
As j = 5m (given),
therefore equation becomes<
5m - m = 152 or 4m = 152 or m = 38 ----------(4)
From (2) and (4), d + m = d + 38 = 176 ==> d = 176 - 38 = 138
d + j = 328 --------------(1)
d + m = 176 --------------(2)
Subtracting (2) from (1):
j - m = 328 - 176 = 152 ---(3)
As j = 5m (given),
therefore equation becomes<
5m - m = 152 or 4m = 152 or m = 38 ----------(4)
From (2) and (4), d + m = d + 38 = 176 ==> d = 176 - 38 = 138
Answered by
1
David , Joseph and Mathew have x, y and z marbles
x + y = 328
x + z = 176
y=5z
by comparing the above three
5z+x=328
z+x=176
subtracting the two equations
we can get
david has 138 marbles
x + y = 328
x + z = 176
y=5z
by comparing the above three
5z+x=328
z+x=176
subtracting the two equations
we can get
david has 138 marbles
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