Question

David applies contact force to hammer a nail in a wooden block. What should he do, so that the nail goes into the wooden block easily even if he applies less force?​

Answer 1

Answer:

mass (m)=1kg

Initial velocity (u) =2m/s

distance covered (s)= 0.01m

using (3)rd equation of motion

v

2

=u

2

=2as

∴ final velocity (v)=0 (nail does not move further)

0=(2)

2

+2a×(0.01)

a=−200m/s

2

Force of impact i..e. applied by hammer

F=ma

=(1kg)(200m/s

2

)

F=200N

Now, using (1) st equation of motion

v=u+at

∵v=0

0=2+(−200)t

t=

−200

−2

t⇒10

−2

sec