Question

David borrowed 4575 on 1 July 1995 and return the amount on 31 December 1996 if the rate of interest is 21/2%.find what amount did he return

Answer 1

Answer:

Simple intrest =720.56

Amount =5295.56

Given:-

• David borrowed money 4575 on 1 july 1995 and return the amount on 31 december 1996.
• rate of interest 21/2%

As above Information

• Principle = 4575
• Rate% = 21/2 %
• Time = 1 july 1995 to 31 december 1996
• means Time = 1 year n 6 months means 18 month.

now ;

First we will solve simple intrest

$simple \: \: intrest = \frac{p \times n \times t}{100} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4575 \times 21 \times 18}{2 \times 100 \times 12} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4575 \times 63}{ 4\times100 } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 720.56 \\ \\ now \: for \: amount \\ \\ as \: we \: know \\ \\ amount \: = principle \: + s \: .i \\ \\ amount = 4575 + 720.56 \\ \\ amount = 5295.56$

Answer 2

David Returned  5295.56 Rs if borrowed 4575 on 1 July 1995 and return the amount on 31 December 1996 at  the rate of interest of 21/2%

Step-by-step explanation:

David borrowed 4575 on 1 July 1995 and return the amount on 31 December 1996

=> P = 4575

   Time = T = 18 Months  = 1.5 Years

   Rate of interest = R = 21/2  = 10.5 %

Simple Interest = P * R * T/100

= 4575 * 10.5 * 1.5/100

= 720.56

Amount David Returned = 4575 + 720.56

= 5295.56 Rs

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