Math, asked by AnzarKhan143, 11 months ago

David borrowed rupees 4575 on 1st July 1995 and return the amount on 31st December 1996 is the rate of interest was 21% but amount did he returned ?

Answers

Answered by GURI292
1

Answer:

principal= ?

Amount =4575

Time =1year

Rate of interest=21percent

4575(1+21÷100)

5535.75

S.I= 5535.75-4575

=960.75

Answered by TanikaWaddle
2

simple interest = Rs. 1441.125

Total amount to be return will be Rs. 6016.125

Step-by-step explanation:

principal = Rs. 4575

rate %m = 21%

time duration = 1 july 1995 to 31 december 1996 = 12+ 6 months = 18 months

= 1.5 years

first we have to find the simple interest

S.I = \frac{p\times r\times t}{100}

putting the values from above

we get

S.I = \frac{4575\times 21\times 1.5}{100}

S.I = \frac{144112.5}{100}

S.I = 1441.125

now

amount = S.I + principal

amount = 1441.125 +4575

amount = Rs. 6016.125

hence ,

simple interest = Rs. 1441.125

Total amount to be return will be Rs. 6016.125

#Learn more:

Simple interest questions = Srinivas borrowed RS.7300 from Mr. Rao on 17th February,1996 and returned the amount on 24th September, 1998. If he paid interest at 21/2% per annum, determine the amount he returned to Mr. Rao

https://brainly.in/question/5819679

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