Question

David borrows and amount of rupees 25000 to repair his house this is borrowed on compound interest of 16% per annum for 2 years what is the total amount he pays at the end of 2 year

Answer 1

P(1+r/100)n

25000(1+16/)2

25000(1+4/25)2

40×29×29/25×25=33640

Answer 2

Answer ●●●●●●●●
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Given,

P = ₹ 25000

R = 16% p.a.

T = 2 years

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Now,

$A = P(1 + \frac{R}{100} ) {}^{t} \\ \\ \: \: \: \: \: =Rs \: 25000 \times ( 1 + \frac{16}{100} ) {}^{2} \\ \\ \: \: \: \: \: = Rs \: 25000 \times \frac{106}{100} \times \frac{106}{100} \\ \\ \: \: \: \: \: = Rs \: 33640$

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I hope it will help you