Math, asked by slefebure001, 1 month ago

David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below.

GFC of 80, 32, and 48: 16
GCF of b4, b2, and b4: b2
GCF of c3 and c: c
GCF of the polynomial: 16b2c
Rewrite as a product of the GCF:
16b2c(5b2) – 16b2c(2c2) + 16b2c(3b2)
Factor out GCF: 16b2c(5b2 – 2c2 + 3b2)
Which statements are true about David’s work? Check all that apply.
1.The GCF of the coefficients is correct.
2.The GCF of the variable b should be b4 instead of b2.
3.The variable c is not common to all terms, so a power of c should not have been factored out.
4.The expression in step 5 is equivalent to the given polynomial.
5.In step 6, David applied the distributive property.

Answers

Answered by siddhesh2356
1

Answer:

10181845555425125424275245

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