Math, asked by bkm7549, 1 month ago

David graduated 8 years ago. ii. David's present age is 6 times his age at the time of graduation ceremony. 5 iii. His sister was 10 years younger to him at that time. Find her present age.​

Answers

Answered by ag21dec1989pa7b0j
1

Step-by-step explanation:

let the present age of David=X

graduated year=X-8

X= 6(X-8)/5

5X=6X-48

X=48

Her sister present age=38

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