David is observing his image in a plane mirror. The distance between the mirror and his image is 4 m. If he moves 1 m towards the mirror, then the distance between David and his image will be(i) 3 m (ii) 5 m(iii) 6 m (iv) 8 m
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The answer is (iii) 6 m.
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"The correct answer will be 6m
This is because in a plane mirror,
object distance is equal to the image distance.
Initial object distance, that is, distance of David from the mirror was 4m.
He then moved 1m towards the mirror. So new object distance is
4m-1m= 3m
Therefore, image distance is also 3m.
So, distance of David from his image will be 3m + 3m = 6m.
"
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