Question

David walks 35 miles toward west, tums right, walks 15 miles. She tu
again and walks 15 miles more. How far is she from the starting point​

Answer 1

Answer:

Answer is 65

mark me as the brainliest

Answer 2

$AC^2=AB^2+BC^2\\AC^2=(15)^2+(20)^2\\=225+400\\=625\\AC=\sqrt{625}\\ AC= 25 mile$

So she is $25mile$ away from starting point.