day was Rs 90, find the number of articles
Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40
square meters
If the area of the triangle is 48 sq.cm
Answers
Answered by
0
Step-by-step explanation:
perimeter of the rectangle = 28 m
area of rectangle = 40 m²
perimeter
2(l + b) = 28
l + b = 28/2
l + b = 14 equ (1)
area = l × b = 40
l = 40/b
substitute l = 40/b in equ (1)
as breadth of rectangle is considered smaller we take b = 4
l = 40/b
l = 40/4
l = 10 m
length of rectangle = 10 m
breadth of rectangle = 4 m
Hope you get your answer
Similar questions