Question

Dayanand had an amount of ₹80 lakh with him he spend 44 lakh for purchasing a rectangular plot of land for cultivation. the length of the plot was 10 more more than 5 times it's breadth. then he made a strong fence of 920m around it and made the land ready for cultivation.
1. what percentage of the money did he use for purchasing the land? a) 50% b) 55% c) 60% d)70%
2. what is the length of the plot he purchased?
a)75m b) 150m c)350m d)385m.
3. what is the cost of ploughing the plot at the rate of rupees 12?
a)₹346500 b)₹67500 c)257000 d)185000.
4. he wanted to make a circular path inside the plot for evening walk. what is the maximum possible outer radius of the path he can make? a)37.5m b)19.5m c)460m d)875m​

Answer 1

Answer:

Step-by-step explanation:

1.c  ⇔√$\int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \alpha \frac{x}{y} \sqrt[n]{x} x^{2}$

2.a

3.d

4.a

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Answer 2

Answer:

1.  (b) 55%

2. (d) 385 m

3. (a) ₹346500

4. (a) 37.5 m

Step-by-step explanation:

Part - 1

Dayanand had an amount of ₹80 lakh with him he spent 44 lakh for purchasing a rectangular plot of land for cultivation.

percentage of the money he used for purchasing the land -

$\frac{44 lakh}{80 lakh} \times 100 = 55 \%$

He spent 55% of the money on purchasing the land.

Part -2

Let the breadth of the plot be = x

then, length = 5x + 10

Given, that the perimeter of the plot = 920 m

then,

$2(l+b) = perimeter\\\\2(5x+10+x) = 920\\\\6x+10 = 460\\\\6x = 450\\\\x = 75 m$

The breadth of the plot = 75 m

The length of the plot = $75\times 5+10 =$ 385 m

Part - 3

The rate of plowing is rupees 12 per m².

Area of the field -

$l\times b= 385\times75=28,875 m^2$

rate for plowing-

$12\times 28,875 = 3,46,500 rupees$

So the rate is ₹ 3,46,500.

Part - 4

Since,

length = 385 m

breadth = 75 m

the diameter of the circle in the plot will be no more than the breadth of the plot.

diameter = 75 m

then, the radius will be = 37.5 m

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