Question

days
19. If 6 boys take 10 hours to pack 30 cartoons,
then how many cartoons can 11 boys pack work-
ing for g hours ?​

Answer 1

$\sf\huge\bold{Answer:}$

Given :

Case 1

No. of boys (M1) = 6

No. of hours (T1)=10

No. of cartoons(C1)=30

Case 2

No. of boys(M2)=11

No. of hours(T2)=g

To find :

No. of cartoons(C2)

Solution :

$\fbox{Formula Used}$

$\sf\purple{:⟶ M1×T1×C1=M2×T2×C2}$

$:⟶6×10×30=11×g×C2$

$:⟶1800=11×g×C2$

$:⟶ \frac{1800}{11 \times g} = C2$

OR

$:⟶C2= \frac{163.63..}{g}$

Number of cartoons that 11 boys can pack working for g hours are

$\sf\huge\purple{= \frac{1800}{11 \times g} }$

Answer 2

Answer :

1st Situation :  

No. of boys (M1) = 6

No. of hours (T1)=10

No. of cartoons(C1)=30

2nd situation :

No. of boys(M2)=11

No. of hours(T2)=g

To find :

No. of cartoons(C2)

Solution :  

Number of cartoons that 11 boys can pack working for g hours are

$\mathrm{\dfrac{1800}{11g}}$

Hope it helps!!