Question

DC = EB and CN = NE (c.p.c.t.).
Thus, in ACAE, the points M and N are the midpoints of AC
and CE respectively.
: MN || AE and MN =- AE = MN || AB|| DC
2
and MN = AE = (AB – EB) = (AB - DC) [: EB =DC).
2
2
2
D
P
С
PLE 8
Q
In the adjoining figure, ABCD is a
Ilgm in which P is the midpoint of DC
and Q is a point on AC such that
1
CQ =- AC. Also, PQ when produced
4
meets BC at R. Prove that R is the
R
A
B
midnoint of BC​

Answer 1

Answer:

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