dc shunt generator with lap winding supplies 5kw and 230 v. armature and field copper loss are 360& 200 w respectively calculate armature current and emf . assume to be 8 pole
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Answer:
417.5v
Explanation:
Eg = for Lap Winding ; Eg = for Wave Winding Eg = Vt + Ia ra + 2Vb ; Ia = Ish + IL ; Ish = ; IL = ; PL = Vt .IL
Where Eg = Generated emf, φ = Flux per pole, Z = total no. of conductors
N = Speed in rpm, P = no. of poles, Vt = terminal voltage, Ia = armature current, IL = Line (load) current , Ish = Shunt field current, Rsh = Shunt Field resistance , Vb = Brush drop, P L= Power output , RL = Load resistance
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