DDA wants to make a rectangular park in the colony.if the length and breadth of the park is decreased by 2 m,then it's area will be decreased by 196 square meters.its area will be increased by 246 square meters if it's length is increased by 3 m and it's breadth is increased by 2 m.Find the length and breadth of the park.
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Solution:-
Let the length and breadth of the rectangular park be 'L' and 'B' respectively.
Case 1-
If the length and the breadth of the park is decreased by 2 m respectively , its area is decreased by 196 square meter.
Therefore, the area will be = (L × B) - 196
(L - 2) (B - 2) = L × B - 196
LB - 2B - 2L +4 = LB -196
- 2B - 2L = - 196 - 4
- 2B - 2L = - 200..................(1)
Case 2-
If the length of the park is increased by 3 m and breadth is increased by 2 m, then its area is increased by 246 square meter.
Therefore, the area will be = (L × B) + 246
(L + 3) (B + 2) = L × B + 246
LB + 3B + 2L +6 = LB + 246
3B + 2L = 246 - 6
3B + 2L = 240................(2)
Adding equation (1) and (2), we get
3B + 2L = 240
- 2B - 2L = - 200
________________
B = 40
________________
Substituting the value B = 40 in equation (2), we get
3B + 2L = 240
3 × 40 + 2L = 240
120 + 2L = 240
2L = 240 - 120
2L = 120
L = 60
So, the length and breadth of the park is 60 m and 40 m respectively.
Answer.
Let the length and breadth of the rectangular park be 'L' and 'B' respectively.
Case 1-
If the length and the breadth of the park is decreased by 2 m respectively , its area is decreased by 196 square meter.
Therefore, the area will be = (L × B) - 196
(L - 2) (B - 2) = L × B - 196
LB - 2B - 2L +4 = LB -196
- 2B - 2L = - 196 - 4
- 2B - 2L = - 200..................(1)
Case 2-
If the length of the park is increased by 3 m and breadth is increased by 2 m, then its area is increased by 246 square meter.
Therefore, the area will be = (L × B) + 246
(L + 3) (B + 2) = L × B + 246
LB + 3B + 2L +6 = LB + 246
3B + 2L = 246 - 6
3B + 2L = 240................(2)
Adding equation (1) and (2), we get
3B + 2L = 240
- 2B - 2L = - 200
________________
B = 40
________________
Substituting the value B = 40 in equation (2), we get
3B + 2L = 240
3 × 40 + 2L = 240
120 + 2L = 240
2L = 240 - 120
2L = 120
L = 60
So, the length and breadth of the park is 60 m and 40 m respectively.
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refer to attachment hope this helps
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