Ddt on exposure to water decomposers half-life = 10 years how much time will it take for its decomposition to 99%
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We know decay equation of a radio active element is given by,
ln(M/M₀) = -kt
where M = final mass
M₀ = initial mass
k = constant
t = time
Given half life of a substance is 10 years, hence,
ln(1/2) = -k x 10
=> -0.7 = -10k
=> k = 0.07
Similarly for 99% decay = 1% mass remains = final mass
=> ln(1/100) = -kt
=> -kt = -4.6
=> t = 4.6/k = 4.6/0.07 = 65.71 years
Hence it will take 65.71 years to decompose to 99% .
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