DE 6 To solve xty = 3: 3x-2y 3: 3 x-2y -4 =0 by determinant method find D
Answers
Answer:
The value of this determinant is found by finding the difference between the diagonally down product and the diagonally up product
now here, the equation is.
x + y = 3
3x - 2y = 4
The denominator determinant, D, is formed by taking the coefficients of x and y from the equations written in standard form.
D = (1/3 * 1/-2)
according to formula,
D = ( 1 ) × ( -2 ) - ( 1 ) × ( 3 )
D = - 2 - 3
D = -5
HENCE, option (C) is correct.
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Answer:
The value of this determinant is found by findings the difference between the diagonally down product and the diagonally up product
now here , the equation is .
x + y = 3
3x - 2y = 4
The denominator determinant, D is formed by taking the coefficients of x and y from the equation writien in standard from .
D = 1 1
3 -2
according to formal ,
D = ( 1 ) x ( -2 ) - ( 1 ) x ( 3 )
D = - 2 - 3
D = -5
Hence , -5 = D .
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