Question

DE and BF are perpendicular to the diagonal AC of a parallelogram ABCD . Prove that DE=BF

Answer 1

In Triangle ADE and Triangle CFB
AD=BC (Opposite sides of a parallelogram are equal)
angle ADE=FCB ( alternate angles )
DEA = CFB(Euclid axiom that all Right angles are equal to one another)
Triangle DEA ~=Triangle BFC (AAS)
DE = BF (CPCT)

Answer 2

Answer:

DE = BF (CPCT)

Step-by-step explanation:

In Triangle ADE and Triangle CFB

AD=BC (Opposite sides of a parallelogram are equal)

angle ADE=FCB ( alternate angles )

DEA = CFB(Euclid axiom that all Right angles are equal to one another)

Triangle DEA ~=Triangle BFC (AAS)

DE=BF(CPCT)

HENCE PROVED

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