Physics, asked by kameenaDEVIL, 7 months ago

de Broglie hypothesis

Answers

Answered by SwaggerGabru
2

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According to de Broglie’s hypothesis, a moving material particle sometimes acts as a wave and sometimes as a particle; or a wave is associated with moving material particle, which controls the particle in every respect. The wave associated with moving particle is called matter wave or de Broglie wave, λ = h/(mv)

Where, m and v are the mass and velocity of the particle and h is Planck’s constant

According to Planck’s quantum theory, the energy of a photon of a radiation of frequency ν and wavelength λ is

E = hν

According to Einstein’s mass-energy relation,

E = mc2

From (i) and (ii), we obtain

hν = mc2

=> m = hv/c2

Since each photon moves with the same velocity c, the momentum of photon,

p = Mass × Velocity

So, p = (hv/c2)× c = hv/c = h/λ

That is,

λ = h/p

This equation is equally applicable to both the photons of radiation and other material particles.

Answered by Dɪʏᴀ4Rᴀᴋʜɪ
4

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Hi!! Here u go for AnsWeR

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According to de Broglie’s hypothesis, a moving material particle sometimes acts as a wave and sometimes as a particle; or a wave is associated with moving material particle, which controls the particle in every respect. The wave associated with moving particle is called matter wave or de Broglie wave, λ = h/(mv)

Where, m and v are the mass and velocity of the particle and h is Planck’s constant

According to Planck’s quantum theory, the energy of a photon of a radiation of frequency ν and wavelength λ is

E = hν

According to Einstein’s mass-energy relation,

E = mc2

From (i) and (ii), we obtain

hν = mc2

=> m = hv/c2

Since each photon moves with the same velocity c, the momentum of photon,

p = Mass × Velocity

So, p = (hv/c2)× c = hv/c = h/λ

That is,

λ = h/p

This equation is equally applicable to both the photons of radiation and other material particles.

\huge\red{Hope\:It \:Help!!}

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