Question

de Broglie wave length of an electron of Kinetic energy 500 eV is
(A)14.82 Å
(B) 24.82 A°
C) 34.82 A°
(D)44.82 A°

plz don't ans blunders for the sake of some points​.... give the correct explanations ...​

Answer 1

Answer:

b) 24.82 A

Explanation:

I hope its right answer

Answer 2

E = hc/λ or λ = hc/E = (6.626 x 10-34 Js)(2.99 x 108 m/s)/(8.1 x 10-17 J) λ = 2.44 x 10-9 m = 2.44 nm, which is about 5 times too big! Wavelength = _____________________.