Question

De broglie wavelength of an electron accelerated by a voltage of 50 volt is close to

Answer 1

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Answer 2

The De broglie wavelength of an electron accelerated by a voltage of 50 volt is 0.173 nm.

Explanation:

In this case, we need to find the ratio of De Broglie wavelength for an electron accelerated through 50 volts. The De Broglie wavelength of electron in terms of potential difference is given by :

$\lambda=\dfrac{h}{\sqrt{2meV} }$

Where  

h is the Planck's constant  

m and e are mass and charge on electron

V is the potential difference

On putting all constant,

$\lambda=\dfrac{1.227}{\sqrt{V} }\ nm$

$\lambda=\dfrac{1.227}{\sqrt{50} }\ nm$

$\lambda=0.173\ nm$

So, the De broglie wavelength of an electron accelerated by a voltage of 50 volt is 0.173 nm.

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