Physics, asked by saranshrock4343, 11 months ago

De broglie wavelength of an electron in the 1st orbit of hydrogen atom

Answers

Answered by chatterjee779

1

Answer:

Explanation:

W.L. = h/mv

= 6.62×10^-34/(9.1×10^-31 × 2.188×10^6)

= 3.3 × 10^-10 m

= 3.3 A

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