de broglie wavelength of an electron travelling one percent speed of light
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De broglie wavelength is given by the ratio of the planks constant and the momentum of the particle
wavelength = h/p = h/mv, where m is mass of particle and p is it's momentum and v is it's velocity
v= speed of light(c) /100
= 6.626*10^-34 Js / 9.1*10^-31 Kg* 3*10^6m/s
= 0.243* 10^-9 m
= 2.43* 10^ -10 m or 2.43 A°
(Because 1A°= 10^-10m)
The debroglie wavelength of the electron is 2.43A°
wavelength = h/p = h/mv, where m is mass of particle and p is it's momentum and v is it's velocity
v= speed of light(c) /100
= 6.626*10^-34 Js / 9.1*10^-31 Kg* 3*10^6m/s
= 0.243* 10^-9 m
= 2.43* 10^ -10 m or 2.43 A°
(Because 1A°= 10^-10m)
The debroglie wavelength of the electron is 2.43A°
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