Question

de Broglie wavelength of an electron travelling with speed equal to one percent of the speed of light

Answer 1

Hii There!!

Since, λ = h/mc 

also, velocity is 1% => c/100

c = 3 × 10^8 m/s

h = 6.63 × 10^-34 J ( Planck's constant )

mass (m) of an electron = 9.1 × 10 ^31 kg

=> λ = 100 h/mc

or λ =  h/mv

          =100h/mc

=> 100 × 6.63 × 10^-34 whole divided by 9.1 × 10^31 × 3× 10^8

=> On solving ,
= 0.241× 10-9 m

       => 0.241 nm   

Or 2.41 (angstorm)



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