Question

De broglie wavelength of an electron with kinetic energy of 120 ev

Answer 1

Answer:

Explanation:

Kinetic energy of the electron, Ek = 120 eV  (Given)

The  planck’s constant, h = 6.6 × 10−34 Js

Mass of an electron, m = 9.1 × 10−31 kg

The charge on an electron, e = 1.6 × 10−19 C

The de Broglie method is the method used to describe the wave properties of matter, generally by the wave nature of an electron. The De Broglie wavelength of an electron having a momentum p, is defined as -

λ = h/p

= 6.6 x 10`-34 / 5.91 x 10`-24

= 1.116 x 10`-10 m

= 0.112

Therefore, the de Broglie wavelength of the electron is 0.112 nm.

Answer 2

Answer:

Explanation:

Kinetic energy of the electron, Ek = 120 eV (Given)

The planck’s constant, h = 6.6 × 10−34 Js

Mass of an electron, m = 9.1 × 10−31 kg

The charge on an electron, e = 1.6 × 10−19 C

The de Broglie method is the method used to describe the wave properties of matter, generally by the wave nature of an electron. The De Broglie wavelength of an electron having a momentum p, is defined as -

λ = h/p

= 6.6 x 10`-34 / 5.91 x 10`-24

= 1.116 x 10`-10 m

= 0.112

Therefore, the de Broglie wavelength of the electron is 0.112 nm.