Chemistry, asked by shweta02, 1 year ago

de-Broglie wavelength of electron in nth orbit of H-atom is (3.18) Å. The value of n is

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Answered by akshith14
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shweta02: btw can u please give the ans also?
Answered by AadilPradhan
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De-Broglie wavelength of electron in nth orbit of H-atom is (3.18) Å.

2πr=n∧

r=radius of first bohr orbit

∧= wavelength of electron

n= n th orbit

n=(2*3.14*0..596)/3.18 =1.165

according to De broglie, every microscopic particle is associated with wavelength.It determines the probability density of finding the object at a given point of the configuration space. De broglie wavelength is inversely proportional to mass of the particle.Hence the wave character of macroscopic particle is negligible.It is related to its momentum, p of the particle.

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