Question

de-Broglie wavelength of electron in the Bohr's orbit is
A)2Pir/n A°
B)2Pirn A°
C)1/n A°
D)n A°​

Answer 1

Answer:

The de Broglie's wavelength of electron present in first Bohr orbit of 'H' atom is 2π×0.529  

A

o

.

First Bohr orbit of 'H' atom has radius r=0.529A  

o

 

Also, the angular momentum is quantised.

mvr=  

2π

h

​  

 

2πr=  

mv

h

​  

=λ

λ=2π×0.529  

A

o