Question

de Broglie wavelength of electron when the operating voltage 10^4 volt is
a) 0. 1227 A° b) 1227 A°
c) 12.27 Aº
d) 1.227 A°
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Answer 1

De - Broglie wavelength of electron when the operating voltage 10⁴ volts is ...

solution : according to De - Broglie wavelength equation,

λ = h/√(2meV)

here h = plank's constant = 6.626 × 10¯³⁴ Js

m = mass of electron = 9.1 × 10¯³¹ kg

e = charge on electron = 1.6 × 10^-19 C

V = voltage = 10⁴ volts

now, λ = (6.626 × 10^-34)/√{2 × 9.1 × 10^-31 × 1.6 ×.10^-19 × 10^4)

= 1.227 × 10¯¹¹ m

= 0.1227 × 10¯¹⁰ m = 0.1227 A°

Therefore the De - Broglie wavelength is 0.1227 A°

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