Math, asked by ykuldeep8422, 1 year ago

De finetti theorem on exchangeable variables explained

Answers

Answered by Anonymous
0
In probability theory, de Finetti's theorem states that exchangeable observations are conditionally independent relative some latent variable. An epistemic probability distribution could then be assigned to this variable. It is named in honor of Bruno de Finetti.

For the special case of an exchangeable sequence of Bernoulli random variables it states that such a sequence is a "mixture" of sequences of independent and identically distributed (i.i.d.) Bernoulli random variables.

While the variables of the exchangeable sequence are not themselves independent, only exchangeable, there is an underlying family of i.i.d. random variables. That is, there are underlying, generally unobservable, quantities that are i.i.d. – exchangeable sequences are mixtures of i.i.d. sequences.

A random variable X has a Bernoulli distribution if Pr(X = 1) = p and Pr(X = 0) = 1 − p for some p ∈ (0, 1).
Similar questions