Question

DE is a line segment parallel to BC of triangle ABC and AD:DB =5:4, find the ratio of area of triangle DEF and area of FBC​

Answer 1

We know AD/DB=5/4

So by BPT ,

AD/DB=DE/BC=5/4

By theorem 6.6 we can say

ar(ΔDEF)/ar(ΔBFC)=(DE/BC)^2

.°.ar(ΔDEF)/ar(ΔBFC)= (5/4)^2=25/16

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