Math, asked by ganesharam727, 4 months ago

De product of two numbers is 2925. If their ICM is 195, find their HCH.
The product of two numbers is 2160. If their HCF is 12, find their CM.
+ The Mof two numbers is 160 and their HCF is 8. If one of the numbers is 32,
find the other number​

Answers

Answered by priyajha4f2019
0
  1. Here, LCM=195

Product of two no.=2925

HCF=?

We know that,

Product of two no.=LCM×HCF

2925=195×HCF

2925/195=HCF

So ,HCF=15

2. Here, HCF=12

Product of two no.=2160

LCM=?

We know that,

Product of two no.=LCM×HCF

2160=LCM×12

2160/12=LCM

So,LCM=180

3. Here,

LCM of two no.=160

HCF of two no.=8

First no.=32

Let other no. will be x

We know that,

Product of two no.=LCM×HCF

32×x=160×8

x=160×8/32

x=160/4

x=40

So, other no.=40

Answered by mohdjaved327
0

it is wrong answer sorry

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