Question

de sin (2:3). ∈ (21-4 + )
​

Answer 1

Step-by-step explanation:

(3−4sin

2

1)(3−4sin

2

3)(3−4sin

2

3

n−1

)

=

sin1sin3sin9...sin3

n−1

sin3

2

...sin3

n

=

sin1

sin3

n

⇒a=3

n

,b=1

∴ for n=1a+b=4

Answer 2

Answer:

n=1a+b+c

hope it's help you