Question

de x^3-3x^2+4x-6 by x-2​

Answer 1

Answer:

first take zero of polynomial of x-2

x-2=0

x=2

f(x)=x^3-3x^2+4x-6

substitute x=2 in f(x)

f(2)=(2)^3-3(2)^2+4(2)-1

=8-12+8-1=16-13=3

remainder:3