Math, asked by senshibangi, 6 months ago

deal?
16. A shopkeeper sold two electronic gadgets for 44000 each. The shopkeeper made a
loss of 12% on one and a profit of 10% on the other. Find his overall gain or loss.
(Hint. Find C.P. of each)

Answers

Answered by ItzDeadDeal
16

Answer:

ANSWER

______________________________________

Solution :-

C.P of both T.V sets = 2 X Rs 10000

= Rs 20000

now,

For first T.V = C.P= Rs 1000

Profit= 10% or Rs 10000

=10 X 10000 = Rs 1000

100

S.P= 10000+1000 = 11000

______________________________________

now 2nd T.V,

C.P = Rs 10000

Loss 10%

Loss = 10% of Rs 10000

= 10 X 10000 = 1000

100

S.P=C.P - Loss

Rs.10000-1000=9000

Total selling price of both T.V set = 11000+9000

=Rs 20000

C.P = S.P

Hence, there is no profit or loss gained by the shopkeeper.

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Answered by sumanthbhat99
6

Answer:

Step-by-step explanation:

44000=(100+10)%CP₁

CP₁=44000*100/110

    =40000

44000=(100-12)%CP₂

CP₂=44000*100/88

     =50000

total cost=90000

total sale=88000

total loss=90000-88000/90000*100

              =2000/90000*100

             =1/45*100

            =2.2222%

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