Question

Dear Friend This Question Is very important Can you solve it ?
Out of three given numbers, the first one is twice the second andthe second is twice the third. The average of the reciprocals of the numbers is 7/72. Find the numbers

Answer 1

Answer:

Of the three numbers, the first is twice the second and the second is twice the third. What is the average of the reciprocal of the number 7/72 of the numbers?

From what I understood from the question I am writing the answer.

Please ask the question correctly.Its incomplete or incorrect questions according to me

Let the third number be x

So second number will be (twice of 3rd)=2x

And first will be (twice of 2nd)=4x

Average of reciprocal of numbers=(1/x+1/2x+1/4x)/3=7/72

Making denominator same

(4/4x+2/4x+1/4x)/3=7/72

(4+2+1/4x)/3=7/72

(7/4x)/3=7/72

7/12x=7/72

12x=72

x=72/12

x=6

Third number is 6

Second is twice of 3rd=2×6=12

First is twice of 2nd=12×2=24

The numbers are 6,12,24