dear guys..... plz do solve these sums for me
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angle y is 40 ,z is 50and x is 90
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3. It is given that PQR is an isosceles triangle in which PQ = QR. We know that in an isosceles triangle the angles opposite to the equal sides are also equal. So, angle P = angle R.
Now, by using angle sum property of a triangle,
angle P + angle R + angle Q = 180°
2×angle R + Angle Q = 180° ( as angle R = angle P )
2×Angle R + 50° = 180° ( angle Q = 50° )
2×angle R = 180-50
angle R = 130/2
angle R = 65°
4.Angle y = 180°-140° ( linear pair )
Angle y = 40°
Angle z = 180-130
Angle z = 50°
Angle x = 180 - (50+40) (Using angle sum property)
Angle x = 90°
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