Question

debroglie wavelength associated with a particleof mass 1mg moving with the velocity of 1metre per sec​

Answer 1

Explanation:

Wavelength = h / momentum

Momentum = 1 mg x 1 m/s

= 10^(-6) x 1

Planck's constant = 6.636 x 10^(-36)

Thus 6.636 x 10^(-36) / 10^(-6)

6.636 x 10^(-30)

Answer 2

Answer:

6.626×10^-31

Explanation:

de broglie wavelength = Planck costant / mass ×velocity

= 6.626×10^-34/1×10^-3 ×1