Math, asked by malikseema262, 1 month ago

DEC is an equilateral triangle in a square ABCD. If BD and
CE intersect at 0 and angleCOD = find the value of X°

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Answered by armanjotsalh
6

Answer:

X = 75

Step-by-step explanation:

Assuming ABCD is the square, and E is the 3rd tip of the equilateral triangle located inside this square: angle BDC = ODC= 45 degrees (formed by a diagonal of the square, BD, with the side of the square, DC); angle OCD = ECD = 60 degrees, because it’s one of the equilateral triangle’s angles. So, in triangle OCD, what is left to make up the difference to 180 degrees? x = 180 -45 -60 = 75

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