Question

deceleration of the bullet in ule wall.
1. An athlete completes one round of a circular track of diameter 50m in 10 seconds. What will be
the distance covered and the displacement at the end of 45 seconds?
ally upwards and then coming​

Answer 1

FIRST the area of park which is πr² so devide 50 by 2 because it is diameter after that we will get 25 which is radius the area we find will be 1962.5m but convert it into km we get 1.962 so distance will get add on which will be 8.829 and for displacement we got for 40s a zero and for five second 0.981

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Answer 2

Explanation:

Time period (time needed to complete one round) = 2π×25/10 = 5π seconds

thus rounds completed in 45 seconds = total time/time period = 45/5π = 9/π

therefore, distance = 9/π×2π×25 = 450 m

Since, complete rounds are zero displacements, so we need to find total complete rounds done in 45 seconds.

so, 9/π ≈ 2.86

thus, straight distance between position at 0.86 of one round and starting position will be considered displacement.

distance in 0.86 of one round = 0.86 × 2π × 25 = 135 m (approx)

Now, angle made by 135 m arc = arc/radius = 135/25 = 5.4

since one full circle makes 6.28 angle, thus remaining angle is 0.88.

thus, displacement = angle × radius = 0.88 × 25 = 22 m