Question

Decide whether 301 is term of given anthmetic progression 5,11,17,23.,....? Verify with help of calculation.​

Answer 1

Answer:

Here, d = □, therefore this sequence is an A.P. a = 5, d = □ Let nth term of this A.P. be 301 tn = a + (n – 1) □ 301 - Algebra. Decide whether 301 is term of given sequence 5, 11, 17, 23, Therefore, 301 is the term of sequence 5, 11, 17, 23,

Answer 2

Here’s your answer:
Given: A.P. = 5,11,17,23,…,…

We have to check whether 301 is a term of the above A.P.

So taking aₙ as 301

a = 5 d = 11 - 5 = 6 aₙ = 301

Using aₙ formula,
aₙ = a + (n - 1)d

301 = 5 + (n - 1)6

301 = 5 + 6n - 6

301 = 5 - 6 + 6n

301 = -1 + 6n

301 + 1 = 6n

302 = 6n

n = 302/6

n = 151/3 or 50.33333

So therefore 301 is not a term of given A.P. 5,11,17,23,…,…

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