Question

Decide whether x=2 and y=-1 is the solution of the equation 2x+y=3 or not?​

Answer 1

Answer:

we have,

\begin{gathered}2x - 3y = 7 \\ 5x + 3y = 7\end{gathered}

2x−3y=7

5x+3y=7

now to check whether the given pair of coordinates is a solution for the pair of linear equations, we simply plug them into the equation.

The first equation,

\begin{gathered}2(2) - 3( - 1) = 7 \\ 4 - ( - 3) = 7 \\ 4 + 3 = 7 \\ 7 = 7\end{gathered}

2(2)−3(−1)=7

4−(−3)=7

4+3=7

7=7

which is true

Now for the second equation,

\begin{gathered}5(2) + 3( - 1) = 7 \\ 10 + ( - 3) = 7 \\ 10 - 3 = 7 \\ 7 = 7\end{gathered}

5(2)+3(−1)=7

10+(−3)=7

10−3=7

7=7

which is also true

Hence, we can conclude that

\begin{gathered}x = 2 \\ y = - 1\end{gathered}

x=2

y=−1

is a solution for the given equations

Answer 2

Answer:

Given:-

Decide whether x = 2 and y = -1 is the solution of the equation 2x + y = 3 or not ?

To Find:-

$2x + y = 3$ is the solution of equation or not.

Note:-

☆》Equation means the both side term should be equal that~ L.H.S = R.H.S

☆》For deciding we need to apply the number which is given.

☆》When there is opposite sign like ' + and - ' the term should be subtracted.

Solution:-

x = 2, y = -1

According to note first point ( L.H.S = R.H.S ) and second point~

● $2x + y = 3$

● $2 × 2 + -1 = 3$

● $4 + (-1) = 3$

According note third point~

● $4 - 1 = 3$

After doing calculations~

● $3 = 3$

♤ Hence, decided that L.H.S = R.H.S or both side term is equal //

Answer:-

$2x + y = 3$ is the solution of equation when x = 2 and y = -1 .