Math, asked by kharatswati69, 7 months ago

Decide whether y=2 is the root of the equation or not
 {y}^{2} - 8y + 10 = 0

Answers

Answered by rajindersandhay
2

Answer:

no it is not root of the equation

Step-by-step explanation:

because by putting the value of y= 2 we will not get zero

= (2)^2 -8(2)+10

= 4 - 16 + 10

= 2

hence not equal to zero

so, it is not root of equation

Answered by jaswasri2006
5

here \: is \: ur \: answer \: buddy \\  \\ mark \: as \: brainliest \: answer \: please \: my \: friend \\  \\ solution \\  \\ take \: y = 2 \: and \: substitute \: in \:  {y}^{2}  - 8y + 10 = 0 \\  \\ then \:  {2}^{2}  - 8(2) + 10  \\  \\ = 4 - 16 + 10  \\  \\  = 14 - 16 \\  \\ =  -2 \\  \\ hence \: this \: is \: a \: root \: equation \:  \\  \\ hope \: this \: will \: help \: u

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