Question

Decode the logic and print the pattern correspondent to given if n=3 then pattern will be 10203010011012**4050809***607

Answer 1

Answer:

Please find the attached file.

Explanation:

total Numbers=N*(N+1)

Every Number i appended with 0

and every row is appended with * with the multiple of 2

c3bec9755ebd7162e2499550b549e146.java

Answer 2

Answer:

import java.util.*;

class Main

{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int num = in.nextInt();

       int star = 0, space, lterm = 1, rterm = num * num+1, i , j;

       for(i = num; i> 0; i--)

       {

           for(space = 1; space <=star; space++)

           {

               System.out.print("*");

           }

           star +=2;

           for(j = 1; j <= i; j++)

           {

               System.out.print(lterm+"0");

               lterm++;

           }

           for(j = 1; j<= i; j++)

           {

               System.out.print(rterm);

               if(j < i)

               {

                   System.out.print("0");

               }

               rterm++;

           }

           rterm = rterm - (i -1) * 2 -1;

           System.out.println();

       }

   }

}

Explanation: