Decode the logic and print the Pattern that corresponds to given input.
If N= 3
then pattern will be :
10203010011012
**4050809
****607
If N= 4
then pattern will be:
1020304017018019020
**50607014015016
****809012013
******10011
Answers
Answered by
23
ANSWER:
There are N number of Rows
1st Row : 1,02....0N 0(N²+1)0(N²+2) ......... 0(N²+N)
2nd Row **(1+N).....(N-1+N) 0(N²- (N - 2)).... 0(N²-1) 0(N²)
.
.
Nth Row 2(N-1)times* (N(N+1)/2 0((N(N+1)/2 + 1)
Explanation:
If N= 3
then pattern will be :
10203010011012
**4050809
****607
If N= 4
then pattern will be:
1020304017018019020
**50607014015016
****809012013
******10011
LOGIC :
There are N number of Rows
1st Row : 1,02....0N 0(N²+1)0(N²+2) ......... 0(N²+N)
2nd Row **(1+N).....(N-1+N) 0(N²- (N - 2)).... 0(N²-1) 0(N²)
.
.
Nth Row 2(N-1)times* (N(N+1)/2 0((N(N+1)/2 + 1)
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