Math, asked by ramyachowdaryvaleti, 1 year ago

Decode the logic and print the Pattern that corresponds to given input. If N= 3 then pattern will be : 10203010011012 **4050809 ****607

Answers

Answered by farhan7465
2

Answer:

dont know bro sorry please

Answered by gaurishankarsharma01
3

Answer:

package tcsnqt;

import  java.util.Scanner;

public class printpattern {

public static void main(String[] args) {

 Scanner sc=new Scanner(System.in);

 int n=sc.nextInt();  

   int a=1,b=n*(n+1)+1,c=0;

   for(int i=n;i>=1;i--)

   {

       for(int j=0;j<c;j++)

       {

           System.out.print("*");

       }

       c=c+2;

       for(int j=a;j<a+i;j++)

       {

           System.out.print(j+"0");

       }

       a=a+i;

     

       for(int j=b-i;j<b;j++)

       {

           if(j==b-1)

               System.out.println(j);

           else

               System.out.print(j+"0");

       }

       b=b-i;

     

   }

   

}

}

Step-by-step explanation:

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