Decompose the number 56 into a product of prime factors, im in 7th grade i dont want a complex answer
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Answered by
1
Answer:
2³×7 (2cube × 7)
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Answer:
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Step-by-step explanation:
So the prime factorization of 56 is 2 × 2 × 2 × 7.
In fact, 2 and 7 are the prime factors of 56. Also, we know that 1 is a factor of every number. Thus, The factors of 56 by prime factorization are 1, 2, 4, 7, 8, 14, 28, and 56.
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